x^2+120x-4500=0

Solution for x^2+120x-4500=0 equation:

x^2+120x-4500=0

a = 1; b = 120; c = -4500;
Δ = b2-4ac
Δ = 1202-4·1·(-4500)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-180}{2*1}=\frac{-300}{2}
=-150
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+180}{2*1}=\frac{60}{2}
=30
$